y^2+6.y+1152=1152

Solution for y^2+6.y+1152=1152 equation:

y^2+6.y+1152=1152

We move all terms to the left:

y^2+6.y+1152-(1152)=0

We add all the numbers together, and all the variables

y^2+6.y=0

a = 1; b = 6.; c = 0;
Δ = b2-4ac
Δ = 6.2-4·1·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.)-6}{2*1}=\frac{-12}{2}
=-6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.)+6}{2*1}=\frac{0}{2}
=0
$